Went into the University for the first time

I went into the university for the first time today. It is less than a kilometer from the apartment. I had to go there to finalize certain documents regarding my accomodation. I arrived at the university during the lunch time and hence I had to wait for a couple of hours for the office staffs to return. During the time, I roamed around the campus. The place is aesthetically pleasing, however, it is pretty small, especially since where I did my bachelor's, IIT Patna, had a campus spread across over 500 acres. I also went to the nearby Lidl to get a few frozen pizzas. I had that for lunch, evening snack and dinner. I had thought about cooking something for dinner, but I felt a bit lazy to do the same. However, I did modify the last frozen pizza by adding some mushrooms, pizza sauce and pepper. I think this could be a good trick moving forward - buy a few frozen pizzas and chopped vegetables from Lidl and fuse them. I think this would make the pizzas a bit more healthier and the effor

Estimating the value of Pi using Monte Carlo Method

The very first moment I was shown this, I was amazed. Estimating something using random events is pretty amazing. The first time I did this in MATLAB, but now, I think I will attempt to do the same in JavaScript.

The undelying concept of Monte Carlo Method is to use randomness to determine the value. The method is often used to solve problems that are hard to determine exactly, when there is enough statistical data available.

Let us define a square centered at the origin with side of length 2. A circle centered at the origin is inscribed in this square.

The assumption that we are using in this method is that if we randomly take a few points within the square, the ratio of the number of points that falls within the circle to the total points taken is equal to that of the area of the square and the circle. That is,

Area of square / area of circle = totalRandomSamples / totalPointsInCircle
Let us write a JavaScript program that could do perform this with a huge number of random sample points generated on the go. To check if the generated point lies within the circle or not, we use pythogoras theorem to calculate the distance from the center.

var squareSide = 2;
var circleRadius = squareSide/2; 
var totalRandomSamples = 100000;
var totalPointsInCircle = 0; 
for(var i = 0; i < totalRandomSamples; i++){
    // A random point contained within the square
    var newX = Math.random() * squareSide - squareSide/2;
    var newY = Math.random() * squareSide - squareSide/2;
    // Check if the new coordinate is inside or outside the circle
    if(Math.sqrt(newX * newX + newY * newY) < circleRadius){
// Area of square / area of circle = totalRandomSamples / totalPointsInCircle
// (squareSide * squareSide) / (pi * circleRadius * circleRadius) = totalRandomSamples / totalPointsInCircle
var pi = squareSide * squareSide * totalPointsInCircle / (circleRadius * circleRadius * totalRandomSamples); 

The value of 𝜋 calculated using the method may vary everytime one runs the code. If you wish to improve the accurace, you can increase the number of Random Samples being used. Also, a better algorithm for generating random points may also be used.

I find that the value calculated is usually within 1% accuracy. The fact that this method simply uses cartesian coordinates to calculate 𝜋 is something that blew my mind.


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